A block of mass m is kept on a horizontal ruler. The friction coefficient between the ruler and the block is µ= 0.5. The ruler is fixed at one end and the block is at a distance L =1 m from the fixed end. The ruler is rotated about the fixed end in the horizontal plane through the fixed end. If the angular speed of the ruler is uniformly increased from zero at a constant angular acceleration 
= 3 rad/sec 2 . Find the angular speed at which block will slip. (g = 10m/s 2 )
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(2 rad/sec.)
Sol. Angular velocity increase with constant angular acceleration α
a c = ω 2 L, a t = α L
a = 
= 
....(1)
for just slipping ⇒ ma = μ mg
⇒ a = μ g .... (2)
form (1) & (2)
μ g = 
ω = 
Ans.
ω = 2 rad/sec.
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